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bdetrent
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Post subject: Is this an error in Guide 1? pg. 151 example Posted: Sun Jun 20, 2010 4:51 am |
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Posts: 1
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x^3 - x = p and x is odd, is p divisible by 24?
p = x(x - 1)(x + 1) -- the guide says "p is divisible by at least 4," because (x - 1) is even and (x + 1) is even cuz x is odd.
However, what if X is 1? Then p = 0
Pls tell me if I'm missing something
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gayathri248
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Post subject: Re: Is this an error in Guide 1? pg. 151 example Posted: Tue Jun 22, 2010 7:15 pm |
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Posts: 10
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0 divided by anything is still 0. Its still considered divisible.
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tim
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Post subject: Re: Is this an error in Guide 1? pg. 151 example Posted: Thu Jul 08, 2010 1:20 pm |
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| ManhattanGMAT Staff |
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Posts: 2242 Location: Southwest Airlines, seat 21C
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Yes, in other words 0 is divisible by 4, and it is in fact divisible by any nonzero integer you can name. Remember, to be divisible by 4, a number n must have the property that n/4 is an integer. Since 0/4 is an integer (0), 0 is divisible by 4. You can of course use this method to verify that 0 is divisible by any integer for which divisibility is defined..
_________________ Tim Sanders Manhattan GMAT Instructor
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