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avarela218
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Post subject: Is the integer X divisible by 36? Posted: Thu Mar 05, 2009 3:54 pm |
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Can somebody clarify this for me?
Is the integer X divisible by 36? 1. X is divisible by 12 2. X is divisible by 9
Isn't the answer "E" because we need to eliminate the redundant "3" when combining the prime boxes. This leaves just two 2's and one 3 when combining prime boxes. Therefore, we dont know if x has two 2's and two 3's.
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saurav.raaj
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Post subject: Re: Is the integer X divisible by 36? Posted: Sun Mar 08, 2009 5:20 pm |
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to find whether X is divisible by 36, X must be divisible by 4 and 9 (or infact 2 x 2 x 3 x 3, i.e. two 2's AND two 3's)
if X is divisible by 12, that means X = k1 x 12 = k1 x 2 x 2 x 3, we are still missing a 3 here. Not Sufficient. (k1 is the other integer factor)
if X is divisible by 9, that means X = k2 x 9 = k2 x 3 x 3, we are still missing a 4 (or 2x 2) here. Not Sufficient. (k2 is the other integer factor)
if we combine both, then we get get X divisible by 12 and 9 which means X = k3 x (12 ~ 2 x 2 x 3) x (9 ~ 3 x 3) (k3 is the other integer factor)
we can re-write this: X = k3 x (12 ~ 2 x 2 x 3) x (9 ~ 3 x 3)
as
X = k3 x 12 x 9 = k3 x 4 x 3 x 3 x 3 = k3 x 36 x 3
So we see, 36 emerges as one of the factors, while k3 x 3 is the other.
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JonathanSchneider
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Post subject: Re: Is the integer X divisible by 36? Posted: Wed Mar 11, 2009 2:22 pm |
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| ManhattanGMAT Staff |
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Posts: 480 Location: Durham, NC
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Well shown.
To the first poster: in simpler terms, just be careful: 12 is 2*2*3. It seems you were forgetting about one of those 2's.
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