tim wrote:
With your approach you can’t just plug e<-12 into either statement, because plugging into statement 2 is inconclusive. However, since you have both statements to use, you still have sufficient information because plugging into 1 tells you d is positive. A better approach though would be to subtract statement 1 from statement 2, getting rid of the e’s you don’t want and keeping the d’s you want:
-2d < 0
d > 0
Thanks Tim.
I wonder how did you "subtract" inequality?
I know you can multiple by -1 as a way to "subtract", but you have to switch the sign when you do that.
So I will multiple (e-d<-12) by -1 and get -e + d > 12
combine/add the rephrased inequality with e + d = -12
I will cancel out e and get 2d > 0 hence d>0, am I right?
Thanks again.