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sarahmailings
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Post subject: In the xy-coordinate plane, line l and linke k intersect... Posted: Mon Nov 01, 2010 6:48 pm |
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DS question from MBA.com CAT #2.
In the xy-coordinate plane, line l and line k intersect at the point (4,3). Is the product of their slopes negative?
(1) The product of the x-intercepts of line l and line k is positive. (2) The product of the y intercepts of line l and line k is negative.
My approach - I was able to get it down to C or E by picturing possible lines on the graph. However, I got stuck between answer choice C or E. I guessed E (the answer is C). Any thoughts about the right answer is C? I'd love suggestions about quicker ways to work it out.
Thanks in advance!
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mschwrtz
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Post subject: Re: In the xy-coordinate plane, line l and linke k intersect... Posted: Fri Nov 05, 2010 12:56 am |
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atul.prasad
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Post subject: Re: In the xy-coordinate plane, line l and linke k intersect... Posted: Sun Nov 14, 2010 3:55 pm |
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Let the lines L and K be given by the equation:
L => y=mx + c K => y=nx + k
since both lines intersect(or pass thru) @ (4,3) we can evaluate c and k in terms of m and n respectively.
so L => y = mx + 3-4m K => y = nx + 3-4n
evaluating statement 1: x intercept for L = (4m-3)/m x intercept for K = (4n-3)/n
If you multiply them you get a fraction dependent on m and n from which you cannot infer anything about the product of slopes
From 2 we know that (3-4m)(3-4n) is -ve or (4m-3)(4n-3) is -ve Even here we cannot establish if the product of mn is -ve
But if we combine the 2 statements 1 says (4m-3)(4n-3)/(mn) is positive From 2 we know that (4m-3)(4n-3) is negative. Hence for 1 to be true, mn must be -ve which is exactly what we need to find out.
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jnelson0612
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Post subject: Re: In the xy-coordinate plane, line l and linke k intersect... Posted: Wed Nov 17, 2010 4:15 pm |
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Thank you everyone!
_________________ Jamie Nelson ManhattanGMAT Instructor
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