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muktarashmi
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Post subject: If x is an integer Posted: Mon Aug 01, 2011 3:01 pm |
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Posts: 15
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If x is an integer, then x(x – 1)(x – k) must be evenly divisible by three when k is any of the following values EXCEPT -4 -2 -1 2 5 (x) and (x – 1) are consecutive, so the three terms would be consecutive if (x – k) is either the lowest of the three, or the greatest of the three:
(x – k), (x – 1), and (x) are consecutive when (x – k) = (x – 2), or k = 2 (x – 1), (x), and (x – k) are consecutive when (x – k) = (x + 1), or k = -1 ....I am convinced about this
but could you please explain this:
Note that the difference between k = -1 and k = 2 is 3. Every third consecutive integer would serve the same purpose in the product x(x – 1)(x – k): periodically serving as the multiple of three in the list of consecutive integers.
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mithunsam
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Post subject: Re: If x is an integer Posted: Tue Aug 02, 2011 2:02 pm |
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Posts: 76
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Another way to write this question is... for what value of k, x(x – 1)(x – k) is not a multiple of 3.
If x(x – 1)(x – k) is not a multiple of 3, then x and (x-1) cannot be a multiple of 3.
Now consider 1,2,X,4,5,X,7,8,X,10,11,X... here X is a multiple of 3
Now consider (x-1) & x are 4 & 5 respectively (keep in mind, x=5). Now go back to the answer choices
A) k = -4 => (x-k) = (5--4) = 5 + 4 = 9 - - - - > multiple of 3 B) k = -2 => (x-k) = (5--2) = 5 + 2 = 7 - - - - > not a multiple of 3, correct answer C) k = - 1 => (x-k) = (5--1) = 5 + 1 = 6 - - - - > multiple of 3 D) k = 2 => (x-k) = (5 - 2) = 3 - - - - > multiple of 3 E) k = 5 => (x-k) = (5 - 5) = 0 - - - - > yes, 0 is a multiple of 3
I hope this would explain your question...
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muktarashmi
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Post subject: Re: If x is an integer Posted: Wed Aug 03, 2011 10:00 pm |
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Posts: 15
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oz_gurses
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Post subject: Re: If x is an integer Posted: Thu Aug 11, 2011 9:12 am |
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Posts: 2
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Hi
my 2 cents:
when added 3 together, it should not be divided to 3.
So, x+x-1+x-k = 3x-1-k Then plug in numbers in the options.
Only B does satisfy the condition.
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jnelson0612
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Post subject: Re: If x is an integer Posted: Sun Sep 11, 2011 11:59 pm |
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Posts: 1857
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That works too!
_________________ Jamie Nelson ManhattanGMAT Instructor
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