agha79 wrote:
I was unable to find below question in the form. I got this question during my GMAT prep exam one. I am not even sure how to get started on this question.
If 5^21 x 4^11 = 2 x 10^n what is the value of n?
A) 11
B) 21
C) 22
D) 23
E) 32
OA: B
First thing to do here is to rewrite the left side of the question by breaking that 4^11 down to a prime factorization. 4^11= (2^2)^11, or 2^22.
Okay, so now we have 5^21 * 2^22. Notice how the right side has 10^n. Maybe we should try to make some 10s on the left side. What if we rewrite the left side as this: 5^21 * 2^21 * 2^1? Now we can combine 5^21 * 2^21 and make 10^21 (plus let's not forget the leftover 2^1, or just 2).
Notice what we have now: 10^21 * 2 = 2 * 10^n. n must be 21, or B.