Nice problem. Initially I thought it is A, but after the following reasoning I chose D. Is there any better way of solving this?
solution:
(1) -2x>3y. If y>0, then x needs to be negative (zero would not work). Sufficient
(2) break down equation as follows
2x+5y-20=0 >> (2x+3y)+2y-20=0>> At this point we note that 2x+3y is negative (given statement), and that -20 is negative. Therefore 5y HAS to be positive. Since -2x>3y, x is negative. Sufficient
if you have further questions, please post them on that thread. thanks.
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