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agalstia
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Post subject: If (1/5)^m x (1/4)^18 = 1/(2x10^35), then m=? Posted: Thu Sep 23, 2010 11:38 pm |
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If (1/5)^m x (1/4)^18 = 1/(2x10^35), then m=?
A) 17 B) 18 C) 34 D) 35 E) 36
OA is D
I tried doing this problem several times in several different ways. I first attempted to split the 10 on the right side into its factors of 2 and 5. I also split the 4 on the rights into its factors of 2x2. However, I was clueless as to how I could combine the fractions, so just ended up guessing A and got it wrong. Please help.
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gokul_nair1984
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Post subject: Re: If (1/5)^m x (1/4)^18 = 1/(2x10^35), then m=? Posted: Fri Sep 24, 2010 12:31 am |
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agalstia
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Post subject: Re: If (1/5)^m x (1/4)^18 = 1/(2x10^35), then m=? Posted: Fri Sep 24, 2010 12:46 am |
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Thanks! I had tried searching it, but it wasn't coming up anywhere.
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vinamragharat
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Post subject: Re: If (1/5)^m x (1/4)^18 = 1/(2x10^35), then m=? Posted: Sat Sep 25, 2010 3:20 am |
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Posts: 1 Location: India, Mumbai
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M=35
Here how it goes, 1/(2x2^35x5^35) = 1/5^m x 1/2^36 (since 1/4^18 = 1/2^36)
Now, we have same BASE, so we can ADD the powers.Therefore,
1/(2^36 x 5^35) = 1/2^36 x 1/5^m
compare. We get,
1/5^m = 1/5^35
M=35
Please refer to MGMAT Guides! They are awesome on this stuff!
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RonPurewal
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Post subject: Re: If (1/5)^m x (1/4)^18 = 1/(2x10^35), then m=? Posted: Mon Oct 04, 2010 8:45 am |
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Posts: 7146
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guys, when someone posts a link to an already existing thread, please post all subsequent comments on that thread, not this one. we don't want a bunch of concurrent threads running on the same problem.
we will henceforth delete all new comments on this thread; if you have anything else to say about this problem, please post it on the thread referred above.
thanks.
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