sm wrote:
if we are told that four different prime numbers are factors of 2n then can't i further assume that one of those four prime numbers is 2 (since it's 2n)
yes.
Quote:
so wouldn't n have 3 different prime factors?? therefore sufficient info to answer the problem?
no.
it's possible that 2 is already a factor of n to start with, in which case n itself would still have 4 different prime factors (because, in that case, the additional 2 would not change the total number of prime factors).
for instance, if n = 3x5x7 = 105 (which has three prime factors), then 2n = 2x3x5x7 = 210 has four prime factors.
if n = 2x3x5x7 = 210, which has four prime factors, then 2n = 2x2x3x5x7 = 420, which still has two prime factors.
therefore, #1 is not sufficient.