lionelpq wrote:
The answer to question 11 says "As we learned in Chapter 1, there are (4+1)(1+1)=10 different factors of 2^4*3." What is this formula refered to in Chapter 1 that gets us to 10? I could not find it.
Thanks!
The formula to find the total number of factors of any number N is:
(a+1)(b+1)(c+1)........
where a, b, c, ..... are the powers of prime factors of the number N.
e.g. N = 72
prime factors of 72= 2X2X2X3X3 = 2^
3 X 3^
2here a = 3 and b = 2
So number of factors of 72 = (3+1)(2+1) = 12