Register    Login    Search    Rss Feeds

 Page 1 of 1 [ 4 posts ] 



 
Author Message
 Post subject: Guide 1: Chapter 4: Question: 11 (pg. 58, 4th edition)
 Post Posted: Tue Jun 29, 2010 5:25 am 
Offline
Students


Posts: 5
The answer to question 11 says "As we learned in Chapter 1, there are (4+1)(1+1)=10 different factors of 2^4*3." What is this formula refered to in Chapter 1 that gets us to 10? I could not find it.

Thanks!


Top 
 Post subject: Re: Guide 1: Chapter 4: Question: 11 (pg. 58, 4th edition)
 Post Posted: Tue Jun 29, 2010 6:03 am 
Offline
Students


Posts: 22
lionelpq wrote:
The answer to question 11 says "As we learned in Chapter 1, there are (4+1)(1+1)=10 different factors of 2^4*3." What is this formula refered to in Chapter 1 that gets us to 10? I could not find it.

Thanks!


The formula to find the total number of factors of any number N is:

(a+1)(b+1)(c+1)........

where a, b, c, ..... are the powers of prime factors of the number N.

e.g. N = 72
prime factors of 72= 2X2X2X3X3 = 2^3 X 3^2

here a = 3 and b = 2

So number of factors of 72 = (3+1)(2+1) = 12


Top 
 Post subject: Re: Guide 1: Chapter 4: Question: 11 (pg. 58, 4th edition)
 Post Posted: Tue Jun 29, 2010 8:48 am 
Offline
Students


Posts: 5
Apreciate it. Thanks


Top 
 Post subject: Re: Guide 1: Chapter 4: Question: 11 (pg. 58, 4th edition)
 Post Posted: Thu Jul 08, 2010 1:44 pm 
Offline
ManhattanGMAT Staff


Posts: 2242
Location: Southwest Airlines, seat 21C
Thanks, Phoenix..

_________________
Tim Sanders
Manhattan GMAT Instructor


Top 
Display posts from previous:  Sort by  
 
 Page 1 of 1 [ 4 posts ] 





Who is online

Users browsing this forum: No registered users and 0 guests

 
 

 
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot post attachments in this forum

Search for:
Jump to: