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anjali
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Post subject: gmat prep - how do i solve this Posted: Sat Jan 31, 2009 4:55 pm |
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Are x and y both positive
(1) 2x-2y=1
(2) x/y >1
OA is C
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michael_shaunn
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Post subject: Posted: Sat Jan 31, 2009 6:47 pm |
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Hi anjali,
I hope that you are familiar with equation of a line and a bit of geometry.
Now just look at the equation 2x-2y=1 which is equal to y=x-0.5 which is an equation of a line.This line will pass through the first , third and the fourth quadrant in a rectangular co-ordinate system(you can roughly draw it and see) which means that x and y need not always be positive though the equation can be satisfied by both x and y being positive at the same time.
Looking at x/y>1 one thing we can be sure of is that magnitude of x must be greater that y and x/y must be positive.
But a negative number divided by a nagative number is also positive.Hence x and y need not always be positive at the same time.
The first clue clarifies that x and y both can be positive(first quadrant) or x positive and y negative(fourth quadrant) or x negative and y negative(third quadrant).
The second clue clarifies that either both are positive or both are begative.
I don't think either of the clues give a certain answer about both being always positive at the same time.
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Khalid
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Post subject: Re: gmat prep - how do i solve this Posted: Sun Feb 01, 2009 9:14 pm |
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anjali wrote: Are x and y both positive
(1) 2x-2y=1 (2) x/y >1
OA is C
Start by plugging numbers
x - y = 0.5
x= 1.5, y = 1, then x - y = 0.5. so x>0 and y>0
x = -0.5 and y = 1, then y = 0.5 but x<0 and y > 0
Insufficient
Statement 2
Does add much
But if you combine both, we see x can't be negetive
Hence C
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guest_z
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Post subject: Posted: Wed Feb 04, 2009 8:27 am |
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I may have missed something but I think there were some inaccuracies above.
-.5 and 1 do not work as solutions for x and y respectively in A. 2(-.5) -2(1) = 1 (-3 <> 1)
If you put in -.5 and -1 that will give you a solution. but positive 2 and 1.5 will also work so x and y can be either neg or pos. (insufficient)
b) this tells that x and y are either both neg or both pos also and that the abs value of x is larger than abs value of y.
Combining the 2 since x has be larger than y, the only way (a) would work is with positive numbers. Hence (C).
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shobuj40
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Post subject: Posted: Wed Feb 04, 2009 2:41 pm |
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Quote: Are x and y both positive
(1) 2x-2y=1 (2) x/y >1
OA is C
St:1
2(X-Y)=1
X-Y=0.5
St:2
X and Y have the same sign. nothing more
Together=1+2
X-Y
1-0.5=0.5 (both X and Y are positive)
-0.5-(-1)=0.5(both X and Y are negative)
now 1/0.5=2>1
-0.5/-1=0.5<1
so answer is C
i think this will help
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guest_z
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Post subject: Posted: Wed Feb 04, 2009 8:25 pm |
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GMAT Staff please help.
We have 3 different answers. I think guest_z nailed it :) but could you confirm what the right approach would be?
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AndreaDB
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Post subject: Re: gmat prep - how do i solve this Posted: Fri Feb 13, 2009 9:31 am |
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Posts: 10
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think it easy: 1) x-y=1/2 .. Positive => x>y since can be: (+,+) or (+,-) or (-,-) : Insuff
2) x/y>1 since x/y>0 since (x,y) have to have the same sign: (-,-) or (+,+) : Insuff
Let's see what we could earn putting together:
2) finding the conditions of existence of the second expression we find that to exist, the expression is x>y for (+,+) and x<y when (-,-) that excludes the ambiguity and put the focus on the case (+,+).
Explaining what I meant: "Dear High School math that with inequalities is unequaliable": x/y>1 => (x-y)/y > 0 => True if (x-y) have the same sign of y so:
· y>0 => x>y in agreement with what implied in the statement 1 · y<0 => x<y in disagreement with what implied in the first statement.
Hope not to have confuse you... I'll leave to Magic Ron the duty to explain the answer in his full clearness.
Andrea
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kanaks123
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Post subject: Re: gmat prep - how do i solve this Posted: Sun Feb 15, 2009 3:26 pm |
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Posts: 3
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My approach as following :
1. x - y = 1/2 => x = y + 1/2. Y can be either positive or negative, therefore X can be + or - number. --- Not sufficient
2. x/y > 1 implies that X and Y has to be of same sign, either both positive or both negative. -- not sufficient
Combining (1) and (2), infact substituting (1) in (2) (y + 1/2)/Y > 1 => 1 + (1/2y) > 1 Substracting 1 from both sides will give (1/2y) > 0, which means Y has to be positive. This inturn means X has to be positive.
Hence answer is (c)
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AndreaDB
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Post subject: Re: gmat prep - how do i solve this Posted: Wed Feb 18, 2009 5:40 am |
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Posts: 10
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kanaks123 wrote: My approach as following :
1. x - y = 1/2 => x = y + 1/2. Y can be either positive or negative, therefore X can be + or - number. --- Not sufficient
2. x/y > 1 implies that X and Y has to be of same sign, either both positive or both negative. -- not sufficient
Combining (1) and (2), infact substituting (1) in (2) (y + 1/2)/Y > 1 => 1 + (1/2y) > 1 Substracting 1 from both sides will give (1/2y) > 0, which means Y has to be positive. This inturn means X has to be positive.
Hence answer is (c) Easy and Efficient! that grinds the question without too much reasonings
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RonPurewal
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Post subject: Re: gmat prep - how do i solve this Posted: Wed Feb 18, 2009 6:34 am |
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| ManhattanGMAT Staff |
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Posts: 7146
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kanaks123 wrote: My approach as following :
1. x - y = 1/2 => x = y + 1/2. Y can be either positive or negative, therefore X can be + or - number. --- Not sufficient
2. x/y > 1 implies that X and Y has to be of same sign, either both positive or both negative. -- not sufficient
Combining (1) and (2), infact substituting (1) in (2) (y + 1/2)/Y > 1 => 1 + (1/2y) > 1 Substracting 1 from both sides will give (1/2y) > 0, which means Y has to be positive. This inturn means X has to be positive.
Hence answer is (c) well done. -- here's a good way to deal with x/y > 1 in ALL situations: break it into 2 cases: x and y both positive vs. x and y both negative. if x and y are both positive, then multiplying by y doesn't change the sign, so, x > y. if x and y are both negative, then multilplying by y does change the lign, so, x < y. therefore, statement (2) means either x > y > 0 or x < y < 0. statement (1) implies that x is bigger than y, so this means that, together, the statements mean x > y > 0. answer (c).
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