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jayshree.pillai
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Post subject: Geometry - Circles & Cylinders Problem Set Posted: Fri Mar 05, 2010 7:03 am |
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Posts: 3
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Hello Everyone,
I am having some trouble with Q#10, in Chap 3 of the Geometry Guide.
"A Rectangular box has dimensions 12X10X8. What is the largest possible volume of a right cylinder places inside the box"
I dont quite get the first line of solution that states: "The radius of the cylinder = 1/2(smaller of the 2 dimensions that for box's bottom, the height can then be equal to remaining dimension of the box"
3 combinations have been considered, for this solution:
BaseXWidthX Height = Volume 8X12X10 = pi*(8/2)^2*10 =160pi 10X12X8 = pi*(10/2)^2*8 =200pi <-- Highest Volume 8X10X12 = pi*(8/2)^2*12 =192pi
My question is, why arent we considering this possiblity? Base=10 & height = 12. Since the cylinder rests on the base, radius would be = 10/2 = 5 In which case, the Volume would be = pi*5^2*12 = 300pi
Any advice would be highly appreaciated.
Thank you, Jayshree
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jayshree.pillai
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Post subject: Re: Geometry - Circles & Cylinders Problem Set Posted: Sat Mar 20, 2010 6:08 am |
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Dear Instructors,
Any insight on this problem would be really helpful.
Thank you, Jayshree
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shazmohdkhan
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Post subject: Re: Geometry - Circles & Cylinders Problem Set Posted: Sun Mar 21, 2010 4:41 am |
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Hi jayshree,
One must take into account that the largest radius of the cylinder that can fit in, will be half of the smaller dimension of the base.
So it would be 4 and not 5.
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esledge
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Post subject: Re: Geometry - Circles & Cylinders Problem Set Posted: Mon Mar 29, 2010 11:14 am |
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Posts: 903 Location: St. Louis, MO
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If the height is 12, the round base of the cylinder would sit on the 8-by-10 base of the box, so shazmohdkhan is absolutely right that a cylinder with radius 5 would be too big to fit.
The only reason you didn't catch this yourself is that you didn't draw a picture (am I right?). There's the take-away: draw a picture even when it seems unnecessary at first.
_________________ Emily Sledge
Instructor
ManhattanGMAT
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