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Geometry, 4th ed. Ch.3 pg 49 #10

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futjim
 Post subject: Geometry, 4th ed. Ch.3 pg 49 #10
 Post Posted: Wed Jul 21, 2010 5:03 am 
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Students


Posts: 7
Location: Japan
Dear all,

I had trouble with the following question. Can anyone help?

10) A rectangular box has the dimensions 12 inches x 10 inches x 8 inches. What is the largest possible volume of a right cylinder that is placed inside the box?

I did 2 trials:
1) r = 6, h = 10
2) r = 5, h = 12

Why are these invalid test subjects?
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phoenix.rkchr
 Post subject: Re: Geometry, 4th ed. Ch.3 pg 49 #10
 Post Posted: Wed Jul 21, 2010 6:55 am 
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Students


Posts: 22
This will be easy if you imagine the box.

Your both trials are incorrect:
1) r = 6, h = 10
In this case, you are taking 12 X 8 as base of the box and 12 as height. If radius of cylinder = 6 then diameter will be 12. Now how the cylinder with diameter of size 12 will be fit in 12 X 8 base? To accommodate the cylinder with radius 6 you need at least box base of size 12 X 12.

2) r = 5, h = 12
Same logic applicable here.

So you need to consider height = 8.

Hope this clears your doubt.
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tim
 Post subject: Re: Geometry, 4th ed. Ch.3 pg 49 #10
 Post Posted: Sat Sep 04, 2010 4:27 pm 
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ManhattanGMAT Staff


Posts: 2242
Location: Southwest Airlines, seat 21C
thanks, phoenix..

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Tim Sanders
Manhattan GMAT Instructor
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abedinbhuiyan
 Post subject: Re: Geometry, 4th ed. Ch.3 pg 49 #10
 Post Posted: Wed Sep 15, 2010 10:09 am 
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Students


Posts: 25
That's how GMAC confuses test takers!!!

BR
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tim
 Post subject: Re: Geometry, 4th ed. Ch.3 pg 49 #10
 Post Posted: Mon Sep 20, 2010 8:01 pm 
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ManhattanGMAT Staff


Posts: 2242
Location: Southwest Airlines, seat 21C
indeed..

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Tim Sanders
Manhattan GMAT Instructor
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