From a bag containing 12 identical blue balls, y identical yellow balls, and no other balls, one ball will be removed at random. If the probability is less than 2/5 that the removed ball will be blue, what is the least number of yellow balls that must be in the bag?
A. 17 B. 18 C. 19 D. 20 E. 21
rags99
Post subject: Re: From a bag containing 12 identical blue balls, y identical
so when you solve: 12 /12+Y = 2/5 y = 18 [editor: this is the solution to the equation, not the inequality. the first proper solution to the inequality is the first number greater than 18, which is 19. mind the problem you're solving!]
Any other solution.
tantrix
Post subject: Re: From a bag containing 12 identical blue balls, y identical
you can also solve this problem by plugging in the answer choices.
note that 2/5 is 40%.
start with (a), since you're looking for the smallest viable solution. (a) --> this would be 12/29, which is greater than 40%. no go. (b) --> this would be 12/30, which is exactly 40%. no go. (c) --> this would be 12/31, which is less than 40%. correct answer.
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