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| fractions & percent problem |
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knyc
Guest
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Can someone help explain the way they answer this question?
[Deleted because poster did not cite author.] Many thanks. |
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| is the answer |
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rschunti
Guest
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is the answer 10/3 gallons?
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| unfortunately, i'm not sure what the answer is... |
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knyc
Guest
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but how did you get to 10/3?
Does anyone else try it and get a different answer? |
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| answer |
| explanation |
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rschunti
Guest
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Let say total capacity be "X"
According to question it is initially half filles which is =X/2----------1 Then 2/3 gallon of water/liquid added totalling=(X/2)+(2/3)----------2 According to question equation number 2 will be 70% of total capacity whch is X Hence following will be equation:- (X/2)+(2/3)=(70/100)(X)---------------------3 upon solving equation (2) X=10/3 gallons. |
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| lowest common denominator |
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knyc
Guest
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thanks so much you guys.
obviously you get the fractions into their lowest common denominators to solve for x, right? |
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Brian Lange
Instructor
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Moving to LCD's is one clear path to take -- some people also like converting the fractions into "easier-to-use" whole numbers. But either approach would get you to the same end result.
Thanks. -Brian lange |
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| "easier to use whole numbers" |
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knyc
Guest
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Thanks Brian.
Can you give me an example of the "easier to use whole numbers" you'd use in this problem? |
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| same answer |
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guest612
Guest
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i just tried to solve your question and got the same answer. i used fractions and solved it this way, if it helps any:
50% already filled. adding 2/3 gallons will increase it to 70%. therefore 2/3 increases the bucket by 20%. 2/3=0.2x 2/3=1/5x x=2/3 * 5 = 10/3 |
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Stacey Koprince
MGMAT STAFF
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Please cite the author of the problem - otherwise, it will be deleted. Thanks!
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| fractions & percent problem |
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