Register    Login    Forum    Search    Rss Feed

Board index » Ask An Instructor » GMAT Math » ManhattanGMAT Math Strategy Guides

It is currently Thu Mar 18, 2010 12:35 pm
All times are UTC - 5 hours
View unanswered posts | View active topics
 



 Page 1 of 1 [ 2 posts ] 
Post a new topic">
Post a reply



EIV Chap 6 Qn 3

Author Message
s1800028
 Post subject: EIV Chap 6 Qn 3
 Post Posted: Sat Jul 04, 2009 1:12 am 
Offline
Course Students


Posts: 3
Hi,

Is there another way to solve this problem?

What I did was this:
G^2 < G
G(G-1) < 0
G < 0 or G < 1
Therefore G<0.
Top 
Ben Ku
 Post subject: Re: EIV Chap 6 Qn 3
 Post Posted: Fri Jul 31, 2009 12:20 am 
Offline
ManhattanGMAT Staff


Posts: 753
Hi,

I don't think your approach to this question is quite right.
Quote:
What I did was this:
G^2 < G
G(G-1) < 0
G < 0 or G < 1
Therefore G<0.


"G(G-1) < 0" does not necessarily lead to "G < 0 or G < 1". In fact, "G < 0 or G < 1" actually means G < 1 (since OR means you must combine both inequalities).

G(G-1) < 0 means that G and (G-1) have opposite signs The only region where this is true is between 0 and 1.

Another way to look at this problem is:
If G^2 < G, the only interval where it's true that the square is smaller than a number is between 0 and 1. (See Number Properties Strategy Guide page 65)

Hope that helps!

_________________
Ben Ku
Instructor
ManhattanGMAT
Top 
Display posts from previous:  Sort by  
 
 Page 1 of 1 [ 2 posts ] 




Board index » Ask An Instructor » GMAT Math » ManhattanGMAT Math Strategy Guides

It is currently Thu Mar 18, 2010 12:35 pm
All times are UTC - 5 hours
View unanswered posts | View active topics
 

Who is online

Users browsing this forum: No registered users and 0 guests

 
 

 
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot post attachments in this forum

Search for:
Jump to: