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cesar.rodriguez.blanco
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Post subject: DS: If p, x, and y are positive integers, y is odd, and p Posted: Mon Aug 31, 2009 5:54 pm |
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| Course Students |
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Posts: 145
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I do not know how to solve this problem. Please help:
If p, x, and y are positive integers, y is odd, and p = x^2 + y^2, is x divisible by 4?
(1) When p is divided by 8, the remainder is 5. (2) x – y = 3
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nitin_prakash_khanna
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Post subject: Re: DS: If p, x, and y are positive integers, y is odd, and p Posted: Mon Aug 31, 2009 10:58 pm |
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Posts: 68
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Hi,
This is how i did it. Hope it helps.
1. p can be represented as p = 8n+5 so p can take values , 13, 21, 29,37, 45.....just plugging in various values of integer n.
Now the next task is to represent all these odd numbers as sum of 2 perfect squares.
13 = 4+9 = 2^2+3^2 this implies x=2, y=3 . As question already told us that y is odd. 21 = cant represnt as sum of two +ve integers 29 = 4+ 25 = 2^2+ 5^2 ....implies x=2, y=5. 37 = 1+36 ....implies y=1 , x=6 45 = 9+36....implies y=3, x=6
So it tells us that x = 2, 6...not divisble by 4.
Hence SUFFICIENT
2. Condition B tells us x-y= 3 and y is odd
so y=1 , x=4 Div by 4 y= 3 , x= 6 Not Div by 4 y= 5, x= 8 Div by 4 y= 7, x=10, Not DIv by 4 So INSUFFICIENT
Whats the OA?
thanks nk.
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vishalsongra
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Post subject: Re: DS: If p, x, and y are positive integers, y is odd, and p Posted: Tue Sep 22, 2009 11:10 pm |
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Ben Ku
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Post subject: Re: DS: If p, x, and y are positive integers, y is odd, and p Posted: Sat Oct 03, 2009 5:58 pm |
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| ManhattanGMAT Staff |
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