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| Divisibilty question - Number properties book |
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Stacey Koprince
MGMAT STAFF
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Hi, I would be happy to help but need you to post the full text of any questions about which you ask - I don't always have access to all of my books when I'm posting (and, in any event, I wouldn't be able to get through everyone's questions if I also had to look up all of the problems). Thanks!
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Guest
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Full Question Is:
If j is divisible by 12 and 10, is j divisible by 24? Book says CANNOT BE DETERMINED. If j is divisible by 12 and by 10, its prime factors include 2,2,3, and 5, as indicated by the prime box to the left. Therefore, any integer that can be constructed as a product of these factors is also a factor o j. 24 = 2 * 2 * 2 * 3. There are only two 2s in the prime box, therefore, 24 is not necessarily a factor of j. I BELIEVE this might be a typo. The factors of 12 and 10 are 2*2*3*5*2, which can make 24. Can you confirm? |
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| Prime Box Overlap |
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Dan Bernstein
MGMAT STAFF
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Howdy. You are definitely not the first person to make this assumption. The key to this problem is understanding the overlap of prime boxes. Let me begin with a simpler example.
If j is divisible by 2 and 4, is j divisible by 8? In this case, the prime box of 2 = 2, and the prime box of 4 = 2*2. However, j does not necessarily have to be divisible by 8, as j could just as easily be 4 (a number divisible by both 2 and 4 but not divisible by 8). The key is recognizing that prime boxes, when combined, and not additive. Instead, when prime boxes overlap in a problem such as this one, take the HIGHER POWER of the specific factor that overlaps. Thus in the problem at hand, the prime box of 12 = 2*2*3, and the prime box of 10 = 2*5. The combined prime box of j must include 3*5*2*2 (one 3, one 5, and the higher power of the shared factor 2). Since 24 = 3*2*2*2, we CANNOT determine whether j is divisible by 24. To check your answer you could also consider actual numbers. If j is divisible by 12 and 10, j could = 60, which is not divisible by 24. J, however, could just as easily = 120, which is divisible by 24. Hope that helps! -dan
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| divisibility #4 Chapter 1 |
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bryang
Guest
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Can you explain question #4......Given that 8 is not a factor of g, is 8 a factor of 2g?
Thanks. |
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| Re: divisibility #4 Chapter 1 |
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Jadran Lee
MGMAT STAFF
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The explanation in our book uses prime boxes. That seems like a good way to think about the problem, but here's an alternative:
We are told that 8 is not a factor of g. So g could be any number that is not a multiple of 8. For example, g could be 3. If g is 3, then 2g is 6. 8 is NOT a factor of 6. Another possibility is that g could be 4. If g is 4, then 2g is 8. 8 IS a factor of 8. From our examples, we can see that the given information (that 8 is not a factor of g) does not imply that 8 is, or is not, a factor of 2g. -Jad
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Guest
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I am really confused as to when to use the prime box overlap principle and when not to, even I thought it was typo and that the answer was Yes.
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Stacey Koprince
MGMAT STAFF
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In general, remember that when combining prime boxes, you can only include the MINIMUM possible. So if you're combining 12 and 10:
12 = 2*2*3 10 = 2*5 When I create a new box, the bare minimum I need to be able to construct both a 10 and a 12 is: 2*2*3*5. From those four numbers, I can create 12, and from those four numbers, I can also create 10. Think about it this way: You're standing outside a store. Inside the store is a big box of fruit. I go in, look in the box, come back out and tell you there are 2 apples and an orange in the box. Then someone else goes in, looks in the box, comes out, and tells you that there are an apple and a banana in the box. Do you definitely know that there are 3 apples in the box? No - that second person have been talking about one of the apples that the first person was talking about. The most we can say definitively is that there are at least 2 apples in the box, not three. Same concept with the prime box - the 12 and the 10 are two separate pieces of info, and they could be using some of the same numbers from the prime box. |
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| Divisibilty question - Number properties book |
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