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| Data Sufficiency -Geometry |
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upinder_chopra
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The sorce is gmatprep, i got this question today.
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Ron Purewal
MGMAT STAFF
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(1)
definitely not sufficient, as the outer dimensions can be any length and width that add up to 15 (which would then give a perimeter of 30). (2) let the longer dimension of each small rectangle = L and the shorter dimension = W. then 2W = L (look at the horizontal line in the middle of the rectangle :: one side of it is covered by two W's, the other side by one L, and both are the same length in total) 4W + 3L = 30 (add up all the pieces of the perimeter; the whole perimeter is 30) if we substitute, as is routine for simultaneous equations, we arrive at 4W + 3(2W) = 30 this can be solved SUFFICIENT (remember that you don't have to solve it!) answer = b |
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KTsincere
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Hey Ron can you explain why you only used 2 of the smaller triangles (4w+3L=30) in the equation rather than using all three of the smaller triangles (6w+4L=30)???
Thanks |
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Ron Purewal
MGMAT STAFF
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because 30 is the perimeter of the figure; the perimeter comprises only those segments that are actually part of the figure's boundary. think about it: you can draw all kinds of other lines through the interior of the figure if you really feel like it; clearly none of those lines will have any effect upon the perimeter of the figure. only the 4 w's and 3 l's around the outside of the large rectangle count. make sense? |
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KTsincere
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Sorry in my last post i wrote tirangles but really meant to say rectangles... duhhh...
Anyway I do understand your point, I appreciate the great clarification! However I do have another concern: isn't assuming the perimeter = 30 a statement carryover from statement 1? Also do you think you can speculate on what level question this would be.... Thanks |
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Stacey Koprince
MGMAT STAFF
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Hmm, yes, what you definitely want to notice is that 2W=L, as Ron says above. And then I'm noticing that his first post was at 2:43a, so perhaps he was a little tired... :)
I want to know the ratio of KN to MN. If I know a relationship between the length and the width, I can write KN and MN in terms of just L or just W. Eg, KN = 2W and MN = 3W So KN/MN = 2W/3W = 2/3. Sufficient. Good catch, KT! |
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| Data Sufficiency -Geometry |
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