ganeshraj wrote:
Cannot we solve the problem with (A) alone,
In triangle ABD , we know : AD=6 ,and B=60 dg.
tan x = opp/adj (x = B )
=> tan 60 = 6/BD.
=> sqrt 3 = 6 /BD.
=> BD = 2 sqrt 3.
Area of the triangle ABD = 1/2 .6. 2 sqrt 3 =>6 sqrt 3.
fyi, you should make sure that you have the skill set to solve 30°-60°-90° triangles without trigonometry. i.e., you should just memorize the ratio of the sides (1:√3:2), so that you don't have to waste precious time setting up trig functions.
...especially since trigonometry is not required on this test!
the only right triangles for which you'll have to determine side lengths are 30-60-90, 45-45-90, and/or triangles for which the pythagorean theorem is all you need.