If x and y are non-zero integers and |x| + |y| = 32, what is xy?
(1) -4x – 12y = 0
(2) |x| – |y| = 16
Consider the question stem: |x| + |y| = 32 Does this equation not mean the following simultaneous equations: x + y = 32 -x -y = 32 -x + y = 32 x -y = 32
Now using Statement -1 we have x = -3y using the info from the q stem and statement -1 we can deduce that:
y = +/-8 & y = +/-16 for these values of y we can get corresponding four different values for x i.e. x = +/- 24 & +/-48
But then a question comes, does the original question stem get satisfied with all set of values of x & y?
we see that only two pairs of x,y satisfy the question stem hence xy is obtained. so Statement-1 is sufficient.
700+
Post subject: Re: CAT DS: Pls suggest flaw in reasoning:
According to the question |x| + |y| = 32. Lets just keep it like this for now. We just need to remember that |x| is the absolute value of x & it is always positive.
According to statement one, -4x – 12y = 0 i.e. x = -3y
"We need not consider values where y = + or - 16 because it doesn't satisfy the condition |x| + |y| = 32."
I suspected the same thing.
Thanks, SC
Correct! :-)
_________________ Jamie Nelson ManhattanGMAT Instructor
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