wow what a question.. where did you find this one...
i have tried to solve this ....
whAT is the value of (a!+b!)(c!+d!)? 1.b!d!=4(a!d!) 2.60(b!c!)=(b!d!)
for writing faster i will not write the factorial sign but please assume its there.
from the question we can get ac+ad+bc+bd 1. now bd=4ad not enough so insufficient 2. again insuffcient.
now when we combine them assume bd=x so ad=x/4 ,bc=x/60 now divinde 1 and 2 we get bd/60bc=4ad/bd we get bd=240ac therfore ac=x/240.
now if substitute all values above we get x+x/4+x/60+x/240 but as we do not have a value of x for me the answer is E.
any suggestions... let me know the original ans... but if i had to guess on the gmat i wud go with a C... it has to bring out a solution and i think sunils solution is correct....
Please do post the original source and answer. If this question does not have an original source posted within seven days I will be forced to delete this thread per forum guidelines.
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