Hi,
Tough one..
We have the absolute value of a is greater than the absolute value of b. This means that positive or negative, the numerical value of a is always greater than the numerical value of b.
Statement 1: a < 0i.e. a is negative
Therefore, a·|b| = negative x positive = negative
We don't know anything about b so we will have to take all three cases in which b is positive or negative or zero. We only know from the question that the numerical value of a is greater than that of b. Lets pick numbers quickly:
Code:
a b a·|b| a-b Is a·|b| < a-b ?
-10 0 0 -10 No
-10 -5 -50 -5 Yes
-10 +5 -50 -15 Yes
Therefore statement 1 is insufficient
Statement 2: ab >= 0We have three situations:
i) a and b are both positive
ii) a and b are both negative
iii) b = 0
Note that "a" cannot be equal to zero because then the absolute value can never be greater than b.
Again, lets make a quick table:
Code:
a b a·|b| a-b Is a·|b| < a-b ?
10 5 50 5 No
-10 -5 50 -5 No
10 0 0 10 Yes
-10 0 0 -10 No
Therefore statement 2 is also insufficient.
Combining 1 and 2, we know that a <0 and ab>=0. This means that b is either negative or zero
Quick table once more:
Code:
a b a·|b| a-b Is a·|b| < a-b ?
-10 -5 50 -5 No
-10 0 0 -10 No
Therefore, statements 1 and 2 together are sufficient and answer is C
Please post the OA
Thanks
Sunil