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| A Manhattan Challenege Problem ---Two Contradicting Answers |
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Saurabh Malpani
Guest
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I guess some problem I have edited the post ------- The following is the correct post (hope so)
Hello, The following Challenege problem was published on 01/09/2006. With My apporach (I don't find anything wrong) I get answer as D but with your apporach (Which is also not wrong) I get C. My apporach is given at the end of the Problem ..Please clarify that that why do we have two contradicting answers. 01/09/06 Question Alex and Brenda both stand at point X. Alex begins to walk away from Brenda in a straight line at a rate of 4 miles per hour. One hour later, Brenda begins to ride a bicycle in a straight line in the opposite direction at a rate of R miles per hour. If R > 8, which of the following represents the amount of time, in terms of R, that Alex will have been walking when Brenda has covered twice as much distance as Alex? (A) R – 4 (B) R / (R + 4 ) (C) R / (R – 8 ) (D) 8/(R – 8 ) (E) R^2 – 4 Answer If we want Brenda's distance to be twice as great as Alex's distance, we can set up the following equation: 2(4T) = R(T – 1), where 4T is Alex's distance (rate × time) and R(T – 1) is Brenda's distance (since Brenda has been traveling for one hour less). If we simplify this equation to isolate the T (which represents Alex's total time), we get: 2(4T) = R(T – 1) 8T = RT – R R = RT – 8T R = T(R – 8 ) R /(R – 8 ) = T This is choice C My Apporach T is the time breda bkies for. In the first hour Alex covers 4 miles. So we can that Distance covered by Alex = 4+4T Distance Covered by Breda is= RT we are given that 2(4+4T) =RT 8+8T=RT 8=T(R- 8 ) T= 8/(R- 8 ) |
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| ManhattanGMAT Challenge Problem Jan 9 2006 |
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Stacey Koprince
MGMAT STAFF
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So close! But you did make a mistake here - the problem asks for Alex's time and you solved for Brenda's time. (Remember, in your set-up, you set the variable T to equal Brenda's time.)
If T = 8/(r- 8 ) and Alex went for an hour more, we have to add 1: T = [8/(r-8 )] + 1 Then get a common denominator so you can add the two: T = 8/(r-8 ) + (r-8 )/(r-8 ) T = (8+r-8 )/(r-8 ) T = r/(r-8 ) answer = C In problems like this one, they'll always give you the other person's time or distance or whatever in the answer choices - so always double check to make sure you're solving for what they want. ETA: apparently an 8 immediately followed by a ) is a shortcut for one of the smiley face emoticons. 8) If you need to use this combo for an actual math problem, just put a space between - as in 8 ) |
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Last edited by Stacey Koprince on Tue May 01, 2007 12:32 am; edited 1 time in total |
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Saurabh Malpani
Guest
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Hey Stacey,
Thank you very Much absolutely Great!!!---- I see where the problem ..I will log this in my Log book....this is what I am trying to avoid Silly mistakes on my Exams!!!! Thank you very much once again!!!! It really helped! |
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| A Manhattan Challenege Problem ---Two Contradicting Answers |
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