The problem is attached.

This one seemed simple enough - but apparently not.

Can someone please provide an explanation for this one please.

Thank you.

The correct answer is 495. The answer that U apparently markedis 24 times the correct answer. Please note that the question states that the order of selection does not count.

I agree with Shaji and his reasoning to keep in mind that order doesn't matter. Since the order in which the 4 sites will be picked doesn't matter, we need to divide the result by 4!.

In a nutshell - no. of ways 4 sites can be picked - (12!)/(4!)(8!)

GMAT 2007

495 is what I got. It is the # of ways 4 sites can be picked out of 12 = 12!/(4! x 8!) = 495

yep, you guys have it!