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A certain business produced x rakes each month ...

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mjfsutherland
 Post subject: A certain business produced x rakes each month ...
 Post Posted: Wed Mar 03, 2010 5:28 pm 
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Students


Posts: 9
As I cant seem to find this problem on the forum anywhere else I am guessing I have missed something very obvious, but when I try to solve it, it gets more complicated than I would expect from a GMAT question. There is obviously a much simpler solution.

A certain business produced x rakes each month from November through February and shipped x/2 rakes at the beginning of each month from March through October. The business paid no storage costs for the rakes from November through February, but it paid storage costs of $0.10 per rake each month from March through October for the rakes that had not been shipped. In terms of x, what was the total storage cost, in dollars, that the business paid for the rakes for the 12 months from November through October?

a) 0.40x
b) 1.20x
c) 1.40x
d) 1.60x
e) 3.20x

OA=c

Thanks
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luc2r4
 Post subject: Re: A certain business produced x rakes each month ...
 Post Posted: Fri Mar 05, 2010 12:01 am 
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Students


Posts: 14
Do you know the OA ?
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mjfsutherland
 Post subject: Re: A certain business produced x rakes each month ...
 Post Posted: Mon Mar 08, 2010 6:39 pm 
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Students


Posts: 9
Sorry I put the OA in white. You can highlight the text to see the answer.

The OA = C
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rajkapoor
 Post subject: Re: A certain business produced x rakes each month ...
 Post Posted: Tue Mar 09, 2010 12:12 am 
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Course Students


Posts: 37
total rakes produced fro Nov- feb = 4x

cost of storage for month of march =(4x - x/2) * 0.10 (we subtract x/2 one time)
cost of storage for month of april = (4x -x/2-x/2)*0.10 - (we subtract x/2 two times )

cost for each month can be captured with this - 4x - ( x/2 * n ) where n is from 1 to 8
for march , n = 1 , for april , n = 2, october = 8

therefore total storage cost = [(4x -x/2) + (4x - x/2*2) + ........ + (4x - x/2*8)]*0.10
rest is just calculation

total = [4x*8 - x/2(1+2.... + 8)]*0.10
= [32x - x/2*(4.5*8)] * 0.10
= [32x - 18x] * 0.10
=14x * 0.10x
= 1.40x

_________________
i ask so i can answer / i answer so i can learn
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sandydiwan
 Post subject: Re: A certain business produced x rakes each month ...
 Post Posted: Wed Mar 10, 2010 2:01 pm 
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Students


Posts: 4
mjfsutherland wrote:
As I cant seem to find this problem on the forum anywhere else I am guessing I have missed something very obvious, but when I try to solve it, it gets more complicated than I would expect from a GMAT question. There is obviously a much simpler solution.

A certain business produced x rakes each month from November through February and shipped x/2 rakes at the beginning of each month from March through October. The business paid no storage costs for the rakes from November through February, but it paid storage costs of $0.10 per rake each month from March through October for the rakes that had not been shipped. In terms of x, what was the total storage cost, in dollars, that the business paid for the rakes for the 12 months from November through October?

a) 0.40x
b) 1.20x
c) 1.40x
d) 1.60x
e) 3.20x

OA=c

Thanks


I solved this within two minutes by using the following approach

Since the question involves x and x/2 , to make calculations easier I took x = 2

So total number of rakes produced from Nov - Feb = 2 * 4 = 8
Storage costs for 8 months between Mar and Oct = .1*(7+6+5+4+3+2+1) = 2.8

From the answer choices , multiple each of them by x = 2 to get 2.8 and only c gives the desired result
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Andrew.Skoller
 Post subject: Re: A certain business produced x rakes each month ...
 Post Posted: Fri Mar 12, 2010 11:44 am 
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Course Students


Posts: 1
I did the same thing, but used 10 instead of 2, so the I didn't have to plug in at the end. I ended up just getting cost = 14, so it was clear that was 1.4x
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mschwrtz
 Post subject: Re: A certain business produced x rakes each month ...
 Post Posted: Tue Mar 30, 2010 4:25 pm 
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ManhattanGMAT Staff


Posts: 506
Nice work. I'll add just one point: the reason that picking a value for x works so neatly is that x shows up not just in the question but also in each of the answer choices. In other words, this is what we call a VIC (Variables in Answer Choices) question.
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