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blue.vikasbhardwaj2
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Post subject: a^2 - b^2 multiple of 4 or not ? Posted: Fri Oct 21, 2011 10:41 am |
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If a, b, and c are integers and abc ≠0, is a2 – b2 a multiple of 4?
(1) a = (c – 1)2
(2) b = c2 – 1
The Answer to the Question is C .
My Solution :
We need to check whether a^2 - b^ 2 = 4k , k =1,2,3,4,....
After solving for a^2 - b^2 we have
a^2 - b^2 = -4c * (c-1)^2
If we have a look , if c = 1 then a^2 - b^2 = 0 (a^2 - b^2 not a multiple of 4)
But if c = -2 then a^2 - b^2 = 72 ( a^2 - b^2 multiple of 4)
Therefore , the Answer should be E
Please let me know where am i going wrong !!!!
Thanks! Vikas
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Rijul Negi
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Post subject: Re: a^2 - b^2 multiple of 4 or not ? Posted: Fri Nov 04, 2011 1:26 pm |
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Is a^2 - b^2 = 4k ?
(a-b)(a+b) => for this to be multiple of 4, a and b should both be either odd or even...
Statement 1; Insufficient because it tells us nothing about b
Statement 2: Insufficient because it tells us nothing about a
Combing the two statements: Lets say c is even, from statement 1, a is odd from statement 2, b is odd hence, (a -b)(a+b) is multiple of 4
Now lets say c is odd, Statement 1 => a is even Statement 2 => b is also even (a-b)(a+b) is multiple of 4
Option C is the correct option.
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jnelson0612
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Post subject: Re: a^2 - b^2 multiple of 4 or not ? Posted: Tue Nov 22, 2011 6:38 pm |
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| ManhattanGMAT Staff |
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Posts: 1857
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Thank you; this is a very nice explanation!
_________________ Jamie Nelson ManhattanGMAT Instructor
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