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rahul_var25
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Post subject: 4th Edition,Math Strategy Guide3 Problemset Page no.187,Q9 Posted: Thu Sep 15, 2011 6:20 am |
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Posts: 2
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Is X3>x2 ? "x3 read as X cube and x2 as x square".
1. x>0 2. x2>x
Rephrasing : x3>x2 x3-x2>0 x2(x-1)>0 this means either both are +ve or both are -ve. Since x2 can never be -ve, therefore (x-1)>0 or x>1 ?
from satement 1) X is positive but it cannot tell anything about x>1 b'coz it could 0<x<1 . Insufficient
from satement 2) X2>0 or X2-X>0 or x(x-1)>0 x>0 and x>1 from here we can infer that "x>1" . So the answer should be B . B'coz it seems sufficient.
But in guide answer is C.
CAN ANYONE EXPLAIN ME. THANK yOU.
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JohnHarris
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Post subject: Re: 4th Edition,Math Strategy Guide3 Problemset Page no.187,Q9 Posted: Thu Sep 15, 2011 1:34 pm |
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Posts: 38
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Hi rahul,
A good approach but you stumbled a bit. Just as in the rephrasing of the question, statement two leads to two possibilities of the two factors which must both be examined, i.e. from satement 2) X2>0 or X2-X>0 or x(x-1)>0 implies we have x and x-1 are either both positive or both negative. From statement 2 alone we do not know that x is greater than zero. So we must allow both of those possibilities. So both x and x-1 could be negative, say, for example, -1/10 and -11/10 in which case x^3 < x^2 and statement two alone is not sufficient.
When you put bot statement (1) and statement (2) together, you can then say, since x is greater than zero [from (1)], x must be greater than 1 [from (2)] and the two statements together are sufficient.
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tim
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Post subject: Re: 4th Edition,Math Strategy Guide3 Problemset Page no.187,Q9 Posted: Sat Sep 24, 2011 1:20 pm |
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| ManhattanGMAT Staff |
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Posts: 2183 Location: Southwest Airlines, seat 21C
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Thanks John. One additional thing the original poster missed is that x^2 need not always be positive - you have to consider the possibility that x=0. Of course, statement 1 deals with this quite effectively once you combine the statements..
_________________ Tim Sanders Manhattan GMAT Instructor
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