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 Post subject: 2+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8=
 Post Posted: Wed Apr 23, 2008 6:40 am 
2+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8=

2^9*
2^10
2^16
2^35
2^37


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 Post subject:
 Post Posted: Wed Apr 23, 2008 8:52 am 
2+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8

= 2 * (1+1+2^1+2^2+2^3+2^4+2^5+2^6+2^7)

= 2 * ( 2 + 2 + 2^2 + 2^3 + 2^4 + 2^5 + 2^6 + 2^7 )

= 2 * 2 * ( 1 + 1 + 2^1 + 2^2 + 2^3 + 2^4 + 2^5 + 2^6 )
...

= 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * ( 1+1 )

= 2 ^ 9


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 Post subject:
 Post Posted: Thu Apr 24, 2008 3:31 pm 
Offline
ManhattanGMAT Staff


Posts: 386
Another approach:

2+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8

2(1+1)+2^2+2^3+2^4+2^5+2^6+2^7+2^8
2(2)+2^2+2^3+2^4+2^5+2^6+2^7+2^8

2^2+2^2+2^3+2^4+2^5+2^6+2^7+2^8
2^2(1+1)+2^3+2^4+2^5+2^6+2^7+2^8
2^2(2)+2^3+2^4+2^5+2^6+2^7+2^8

2^3+2^3+2^4+2^5+2^6+2^7+2^8
2^3(1+1)+2^4+2^5+2^6+2^7+2^8
2^3(2)+2^4+2^5+2^6+2^7+2^8

2^4+2^4+2^5+2^6+2^7+2^8
...
2^8+2^8
2^9


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