Challenge Problem Showdown
Manhattan GMAT invites you to test your GMAT knowledge for a chance to win! Each week, we will post a new Challenge Problem for you to attempt. If you submit the correct answer, you will be entered into that week’s drawing for a free Manhattan GMAT Prep item. Tell your friends to get out their scrap paper and start solving!
Please note: We email the winner directly every week, and provided we then receive consent from the winner we post his or her name on our Facebook Fan Page.
Good luck! These are tough problems!
This Week's Problem: "Riemann Oh Man"
For all positive integers n and m, the function A(n) equals the following product:
(1 + 1/2 + 1/22)(1 + 1/3 + 1/32)(1 + 1/5 + 1/52)…(1 + 1/pn + 1/pn2), where pn is the nth smallest prime number, while B(m) equals the sum of the reciprocals of all the positive integers from 1 through m, inclusive. The largest reciprocal of an integer in the sum that B(25) represents that is NOT present in the distributed expansion of A(5) is
