GMAT Challenge Problem Showdown: October 28, 2013

Lauren Golin —  October 28, 2013 — Leave a comment

challenge problem
We invite you to test your GMAT knowledge for a chance to win! Each week, we will post a new Challenge Problem for you to attempt. If you submit the correct answer, you will be entered into that week’s drawing for a free Manhattan GMAT Prep item. Tell your friends to get out their scrap paper and start solving!

Here is this week’s problem:

 

A computer company prices its models using the formula P = (1.25s)a, where is the price per unit, is a constant, and s is the speed rating, from 1 to 20, of the product. The company also grants a discount of 10% on orders of 100 to 249 units and a discount of 25% on orders of 250 or more units. Lotte orders 300 computers, all with the same speed rating. How many computers could she have purchased for the same price if she had chosen models with a speed rating 2 higher than the ones she chose?

GMAT Challenge ProblemTo see the answer choices, and to submit your answer, visit our Challenge Problem Showdown page on our site.

Discuss this week’s problem with like-minded GMAT takers on our Facebook page.

The weekly winner, drawn from among all the correct submissions, will receive One Year of Access to our Challenge Problem Archive, AND the GMAT Navigator, AND Our Six Computer Adaptive Tests ($92 value).

Lauren Golin

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